引用:

原帖由 rucrazy 於 31-8-2006 04:34 PM 發表
the following is a result of  

if the horse run in place or lose in a short length (like less than 3 horses) in the same distance(same course).
wat happen if the horse next run in same distance ...

I am quite interested to know the average odds of such 11.41% winners, do you have such record ?

引用:

原帖由 rucrazy 於 1-9-2006 01:59 PM 發表
actually u can use the excel file i put here to calculate urself..

for the 11.41% the avg odd is 7.2786798.

so if u use fix amount to bet. u will lose money.

so its not a report show u wa ...

I do believe every research or data analysis we did on horse racing are aim to win money. It is obviously that 11.41% winner plus average odd ~ 7.28 cannot bet by fix amount or even by fix percentage of a pool. Do you have an idea on how to make use of such findings to win ?

Let's take a look into last season. There were totally 708 races, i.e. 708 winners. And totally number of horses taken place were roughly 9100. If you randomly select a horse to bet win without any other reason, the prop. you will win is 708/9100 = 7.78%. While this prop. compare with the stated 11.41%, less than 4 winners different after bet 100 times, what do you think ?

It seems you misunderstood what I want to point out. My point is while any research or data analysis which cannot aim to win money, we have to modify and make more assumptions to improve. Otherwise, such research or data analysis are meaningless, do you agree ?

意思是 : 若然所做出的研究或數據分析是對贏錢沒有顯見的意義時, 便應更深入剖析, 改良及假設去改善, 否則這些東西便是沒有用處.

11.41% avg odds is 7.28
7.78% avg odds is 10.18

你認為那一個有意思 ? 我倒覺得 2 個均無意思. 按你所述, 一匹馬在同場地同路程輸近再出同場地同路程預計會有表現, 差不多係人都會有這個想法, 有何希冀 ? 只得 1 成多的勝出率兼多數熱門, 全是欠投注價值的東西.

若然你可分辨出那些會 win, 那些會輸, 那才是價值. 即如我先前所述 "make assumptions"; 例如, 將這些馬匹按齡, 厩, 班, 賠率, 騎師等等區分. 假設這個條件隔晚 5 倍以下全勝, 10 倍以上全敗, 那才是意義.